Question:
write the corresponding value of x and y for which the length of conductors X=4ohm and y=48×10^-8ohm-m are reduced to half
Answer:
Let us assume that the conductor is of length L.
Its resistance = x = 4 ohm; resistivity = y = 48 x 10-8 ohm
When the length is reduced to half, that is L/2, material of the conductor remains the same.
Then y becomes 48 x 10-8 ohm metre.
Since the area of cross section of the conductor is not charged and only length is changed. Length is directly proportional to resistance.
So the new resistance is 4/2 = 2 ohm.
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